document.write( "Question 1058234: How to show that if X1 and X2 are the two roots of $\"+ax%5E2%2Bbx%2Bc=0+\"$ , then $\"+X1X2=c%2Fa+\"$
\n" ); document.write( "and X1+X2=-b/a , where a is not equal 0 ? \n" ); document.write( "

Algebra.Com's Answer #673265 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
(1) $\"+a%2Ax%5E2+%2B+b%2Ax+%2B+c+=+0+\"$
\n" ); document.write( "Divide both sides by $\"+a+\"$
\n" ); document.write( " $\"+x%5E2+%2B+%28b%2Fa%29%2Ax+%2B+c%2Fa+=+0+\"$
\n" ); document.write( "----------------------------
\n" ); document.write( "Roots are $\"+x%5B1%5D+\"$ , and $\"+x%5B2%5D+\"$
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\n" ); document.write( "(2)

\n" ); document.write( "Comparing (1) and (2),
\n" ); document.write( " $\"+x%5B1%5D+%2B+x%5B2%5D+=+-b%2Fa+\"$
\n" ); document.write( " $\"+x%5B1%5D%2Ax%5B2%5D+=+c%2Fa+\"$ \r
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