document.write( "Question 1058228: If a projectile is shot vertically into the air (from the ground) with an initial
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document.write( "velocity of 176 feet per second, its distance y (in feet) above the ground t
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document.write( "seconds after it is shot is given by y=176t+16t^2 (neglecting air resistance)
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document.write( "a. Find the time when y = 0 and interpret the results physically.
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document.write( "b. Find the times when the projectile is 16 feet off the ground. Compute answer
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document.write( "to two decimal places. \n" );
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Algebra.Com's Answer #673253 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! y=0. Note, the square term is always negative. \n" ); document.write( "-16t^2+176t=0 \n" ); document.write( "-16t(t-11)=0 \n" ); document.write( "t=0, t=11 \n" ); document.write( "t=0 is the starting point; t=11 the end point, when it hits the ground. \n" ); document.write( "When the projectile is 16 feet off the ground, -16t^2+176t=16 \n" ); document.write( "-16t^2+176t-16=0 \n" ); document.write( "factor out a -16 \n" ); document.write( "-16(t^2-11t+1)=0 \n" ); document.write( "t=(1/2)(11+/- sqrt (121-4); sqrt (117)=10.82 \n" ); document.write( "t=(1/2)(11+/- 10.82) \n" ); document.write( "t=(1/2)(21.82) or (1/2)(0.18) \n" ); document.write( "t=0.09 sec and 10.91 sec (note symmetry) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |