document.write( "Question 1058221: A committee has seven men and four women.
\n" ); document.write( "If four people are selected to go to a​ conference, what is the chance that the group is two men and two​ women?
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Algebra.Com's Answer #673252 by Boreal(15235)\"\" \"About 
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There are 11C4 ways to go or 330 ways.
\n" ); document.write( "There are 7C2 ways to choose the men (21)
\n" ); document.write( "There are 4C2 ways to choose the women (6)
\n" ); document.write( "They are independent, meaning the choice of men does not affect the choice of the women.
\n" ); document.write( "That product is 126
\n" ); document.write( "The probability is 126/330, or 21/55
\n" ); document.write( "The other choices should add up to 204
\n" ); document.write( "one man, 3 women is 7*4=28
\n" ); document.write( "no men, 4 women is 1 way
\n" ); document.write( "3 men, 1 woman is 35*4=140 ways
\n" ); document.write( "4 men, 0 woman is 35 ways
\n" ); document.write( "They add up to 204.
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