document.write( "Question 1058185: \"I am a 4-digit odd number where the sum of my digits Is 22. the difference between my first digit and my last digit is equal to my third digit. my second digit is twice my third digit. My first digit is the domain value of f(x)=9x+3 if it's corresponding range value is 66.\" What's my number? \n" ); document.write( "
Algebra.Com's Answer #673219 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \"I am a 4-digit odd number where the sum of my digits Is 22. \n" ); document.write( " \r\n" ); document.write( "a = first digit\r\n" ); document.write( "b = second digit\r\n" ); document.write( "c = third digit\r\n" ); document.write( "d = fourth (last) digit\r\n" ); document.write( "\r\n" ); document.write( "a + b + c + d = 22 and d is oddthe difference between my first digit and my last digit \n" ); document.write( "is equal to my third digit. a - d = cmy second digit is twice my third digit. b = 2cMy first digit is the domain value of f(x)=9x+3 if \n" ); document.write( "its corresponding range value is 66.\" \r\n" ); document.write( "We find the value of x for which f(x) = 66 by setting\r\n" ); document.write( "\r\n" ); document.write( "f(x) = 66\r\n" ); document.write( "9x+3 = 66\r\n" ); document.write( " 9x = 63\r\n" ); document.write( " x = 7\r\n" ); document.write( "\r\n" ); document.write( "So the domain value for the range value of 66 is 7\r\n" ); document.write( "Therefore the first digit = a = 7\r\n" ); document.write( "\r\n" ); document.write( "The information so far is:\r\n" ); document.write( "\r\n" ); document.write( "(1) a + b + c + d = 22 and d is odd\r\n" ); document.write( "\r\n" ); document.write( "(2) a - d = c\r\n" ); document.write( "\r\n" ); document.write( "(3) b = 2c\r\n" ); document.write( "\r\n" ); document.write( "(4) a = 7\r\n" ); document.write( "\r\n" ); document.write( "Substituting 7 for a in (1) and (2)\r\n" ); document.write( "\r\n" ); document.write( "(1) a + b + c + d = 22 and d is odd\r\n" ); document.write( " 7 + b + c + d = 22 and d is odd\r\n" ); document.write( "(5) b + c + d = 15 and d is odd\r\n" ); document.write( "\r\n" ); document.write( "(2) 7 - d = c\r\n" ); document.write( " 7 = c + d\r\n" ); document.write( "(6) c + d = 7\r\n" ); document.write( "\r\n" ); document.write( "Subtracting (6) from (5):\r\n" ); document.write( "\r\n" ); document.write( "(5) b + c + d = 15 and d is odd\r\n" ); document.write( "(6) c + d = 7\r\n" ); document.write( "------------------------\r\n" ); document.write( " b = 8\r\n" ); document.write( "\r\n" ); document.write( "Substituting 8 for b in (3)\r\n" ); document.write( "\r\n" ); document.write( "(3) b = 2c\r\n" ); document.write( " 8 = 2c\r\n" ); document.write( " 4 = c\r\n" ); document.write( "\r\n" ); document.write( "Substituting 4 for c in (6)\r\n" ); document.write( "\r\n" ); document.write( "(6) c + d = 7\r\n" ); document.write( " 4 + d = 7\r\n" ); document.write( " d = 3 <-- yes, d is odd.\r\n" ); document.write( "\r\n" ); document.write( "So now we have a=7, n=8, c=4, d=3What's my number? 7843\r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |