document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1058192>Question 1058192</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x + 3y = -3<BR>\n" );
document.write( "whats the slope of the line? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #673212 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=673212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rewrite it putting one y on the left<BR>\n" );
document.write( "2x+3y=-3<BR>\n" );
document.write( "3y=-2x-3<BR>\n" );
document.write( "divide by 3 both sides<BR>\n" );
document.write( "y=(-2/3)x-1<BR>\n" );
document.write( "The slope is the number in front of the x, or -2/3. </SPAN>\n" );
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