document.write( "Question 1058176: A truck traveled the first 100 miles of a trip at one speed and the last 135 miles at an average speed of 5 miles per hour less. The entire trip took 5 hours. What was the average speed for the first part of the trip? \n" ); document.write( "
Algebra.Com's Answer #673210 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 100 miles at x mph, and the time was 100/x hours. Speed*time=distance. \n" ); document.write( "135 miles at (x-5) mph, and the time was 135/(x-5). \n" ); document.write( "Those two add to 5. \n" ); document.write( "(100/x)+(135/(x-5)=5 \n" ); document.write( "multiply everything by x*(x-5) \n" ); document.write( "100(x-5)+135x=5x^2-25x \n" ); document.write( "100x-500+135x=5x^2-25x \n" ); document.write( "5x^2-260x+500=0 \n" ); document.write( "x^2-52x+100=0, dividing everything by 5 \n" ); document.write( "(x-2)(x-50)=0 \n" ); document.write( "x=2,50, only 50 makes sense \n" ); document.write( "Truck went 50 mph for the first two hours ANSWER \n" ); document.write( "It went 45 mph for the next 3 hours, or 135 miles. \n" ); document.write( " \n" ); document.write( " |