document.write( "Question 1058182: Find three consecutive odd integers such that twice the sum of the first and second is one less than three times the third. \n" ); document.write( "
Algebra.Com's Answer #673194 by math_helper(2461)\"\" \"About 
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Let:
\n" ); document.write( " n = smallest of the 3 odd numbers
\n" ); document.write( " n + 2 = 2nd consecutive odd number
\n" ); document.write( " n + 4 = 3rd consecutive odd number\r
\n" ); document.write( "\n" ); document.write( "\"Twice the sum of the 1st and 2nd\" is
\n" ); document.write( " 2((n)+(n+2))\r
\n" ); document.write( "\n" ); document.write( "\"One less than 3 times the 3rd\" is
\n" ); document.write( " 3(n+4) - 1\r
\n" ); document.write( "\n" ); document.write( "—
\n" ); document.write( "Set the two equal:
\n" ); document.write( "\"+2%28%28n%29+%2B+%28n%2B2%29%29+=+3%28n%2B4%29-1+\"
\n" ); document.write( "\"++4n+%2B+4+=+3n+%2B+12+-+1+\"
\n" ); document.write( "\"+++n+=+7+\"\r
\n" ); document.write( "\n" ); document.write( "—
\n" ); document.write( "Ans: The three odd numbers are 7, 9, and 11
\n" ); document.write( "—\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( " 2(7+9) = 32
\n" ); document.write( " 3(11) - 1 = 32 (ok) \r
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