document.write( "Question 1058182: Find three consecutive odd integers such that twice the sum of the first and second is one less than three times the third. \n" ); document.write( "
Algebra.Com's Answer #673194 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! Let: \n" ); document.write( " n = smallest of the 3 odd numbers \n" ); document.write( " n + 2 = 2nd consecutive odd number \n" ); document.write( " n + 4 = 3rd consecutive odd number\r \n" ); document.write( "\n" ); document.write( "\"Twice the sum of the 1st and 2nd\" is \n" ); document.write( " 2((n)+(n+2))\r \n" ); document.write( "\n" ); document.write( "\"One less than 3 times the 3rd\" is \n" ); document.write( " 3(n+4) - 1\r \n" ); document.write( "\n" ); document.write( "— \n" ); document.write( "Set the two equal: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "— \n" ); document.write( "Ans: The three odd numbers are 7, 9, and 11 \n" ); document.write( "—\r \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( " 2(7+9) = 32 \n" ); document.write( " 3(11) - 1 = 32 (ok) \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |