document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1058162>Question 1058162</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many cubic yards of earth must be removed in digging an artificial lake 15 feet deep,if the level bottom is a rectangle 180 feet by 20 feet and the top is a rectangle 216 feet by 24 feet?pls show drawing if possible thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #673185 by </B><A HREF=/tutors/aboutme.mpl?userid=solve_for_x><B>solve_for_x(190)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solve_for_x><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=673185\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The volume described in this problem is a truncated rectangular pyramid.\r<BR>\n" );
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document.write( "The volume is given by:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+%281%2F3%29%28A1+%2B+A2+%2B+sqrt%28A1+%2A+A2%29%29%28h%29 ALIGN=MIDDLE  ALT=\"V+=+%281%2F3%29%28A1+%2B+A2+%2B+sqrt%28A1+%2A+A2%29%29%28h%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "where A1 is one base area, A2 is the other base area (it doesn't matter which is which),<BR>\n" );
document.write( "and h is the height.\r<BR>\n" );
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document.write( "For this problem:\r<BR>\n" );
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document.write( "A1 = 180 * 20 = 3600\r<BR>\n" );
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document.write( "A2 = 216 * 24 = 5184\r<BR>\n" );
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document.write( "h = 15\r<BR>\n" );
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document.write( "The volume is then:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+%281%2F3%29%283600+%2B+5184+%2B+sqrt%283600+%2A+5184%29%29%2815%29+=+65520 ALIGN=MIDDLE  ALT=\"V+=+%281%2F3%29%283600+%2B+5184+%2B+sqrt%283600+%2A+5184%29%29%2815%29+=+65520\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Converting 62,520 cubic feet to cubic yards gives:\r<BR>\n" );
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document.write( "(65520 cu ft)(1 cu yd / 27 cu ft) = 2,426.67 cubic yds </SPAN>\n" );
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