document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=92473>Question 92473</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534494498/algebrahomeworkh>Algebra and Trigonometry</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Given that (3x-a)(x-2)(x-7)=3x cubed-32x squared+87x-70, determine the value of a. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #67318 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=67318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given that (3x-a)(x-2)(x-7)=3x^3-32x^2+87x-70, determine the value of a<BR>\n" );
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document.write( "The last term of the 1st product is (-a)(-2)(-7) ] -14a<BR>\n" );
document.write( "The last term of the 2nd product is -70<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "last term of 1st product = last term of 2nd product<BR>\n" );
document.write( "-14a = 70<BR>\n" );
document.write( "a = -5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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