document.write( "Question 1058147: how to evaluate log base 2 1/6 \n" ); document.write( "
Algebra.Com's Answer #673169 by solve_for_x(190)\"\" \"About 
You can put this solution on YOUR website!
The change of base formula is:\r
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\n" ); document.write( "\n" ); document.write( "where \"log\" is the common base-10 logarithm, and \"ln\" is the
\n" ); document.write( "base-e natural logarithm. You can use either one.\r
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\n" ); document.write( "\n" ); document.write( "To evaluate log2 (1/6) then:\r
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\n" ); document.write( "\n" ); document.write( "log2 (1/6) = log(1/6) / log(2) ≈ -2.5850\r
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\n" ); document.write( "\n" ); document.write( "As a check, \"2%5E-2.5850+=+0.1666+=+1%2F6\"
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