document.write( "Question 1058067: Find three consecutive odd natural numbers such that the product of the first and the last is 11 greater than two times the middle one. \n" ); document.write( "

Algebra.Com's Answer #673105 by jorel555(1290) $\"\"$ $\"About$

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Let n be the first odd number. Then the next numbers in sequence will be n+2 and n+4. So:
\n" ); document.write( "n(n+4)=2(n+2)+11
\n" ); document.write( "n²+4n=2n+15
\n" ); document.write( "n²+2n-15=0
\n" ); document.write( "(n+5)(n-3)=0
\n" ); document.write( "n=3 or -5
\n" ); document.write( "Throwing out the negative answer, we get the consecutive odd numbers as 3, 5, and 7. ☺☺☺☺ \n" ); document.write( "

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