document.write( "Question 1058046: If x=3 or -4 are the solutions of the equation x^2+ax+b=0. Find the value of a and b.
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Algebra.Com's Answer #673076 by solve_for_x(190)\"\" \"About 
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Substituting x = 3 in the equation gives:\r
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\n" ); document.write( "\n" ); document.write( "9 + 3a + b = 0\r
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\n" ); document.write( "\n" ); document.write( "Then substituting x = -4 into the equation gives:\r
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\n" ); document.write( "\n" ); document.write( "16 - 4a + b = 0\r
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\n" ); document.write( "\n" ); document.write( "Subtracting the first equation from the second gives:\r
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\n" ); document.write( "\n" ); document.write( "(16 - 9) + (-4a - 3a) + (b - b) = 0\r
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\n" ); document.write( "\n" ); document.write( "7 - 7a = 0\r
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\n" ); document.write( "\n" ); document.write( "7a = 7\r
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\n" ); document.write( "\n" ); document.write( "a = 1\r
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\n" ); document.write( "\n" ); document.write( "Substituting a = 1 into 9 + 3a + b = 0 then gives:\r
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\n" ); document.write( "\n" ); document.write( "9 + 3(1) + b = 0\r
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\n" ); document.write( "\n" ); document.write( "12 + b = 0\r
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\n" ); document.write( "\n" ); document.write( "b = -12\r
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\n" ); document.write( "\n" ); document.write( "Solution: a = 1, b = -12
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