document.write( "Question 1058030: A man age is 4 times the total age of of 3 sons .after 8 yrs ,his age would be twice the total age of his 3 sons .if the total present of 3 sons is x yrs . find the age of man \n" ); document.write( "
Algebra.Com's Answer #673050 by solve_for_x(190)![]() ![]() ![]() You can put this solution on YOUR website! If the father's age is four times the current sum of the children's ages, x, then \n" ); document.write( "the father's age can be represented by 4x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In 8 years, the father's age will be 4x + 8.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum of the children's ages will be x + 24, since each of the three children will be 8 years older.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the father's age will be twice the sum of the children's ages, you can write:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4x + 8 = 2(x + 24)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4x + 8 = 2x + 48\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4x - 2x + 8 = 48\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x + 8 = 48\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x = 48 - 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x = 40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The current age of the man is 4x = 4(20) = 80 years old. \n" ); document.write( " \n" ); document.write( " |