document.write( "Question 1058013: If half of the complement of a certain angle is 1° more than one-sixth of the supplement of the angle, find the angle. \n" ); document.write( "
Algebra.Com's Answer #673048 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "If half of the complement of a certain angle is 1° more than one-sixth of the supplement of the angle, find the angle.
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Let angle be A
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document.write( "Then its complement is 90 - A, and its supplement is 180 - A
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document.write( "We then get: \"%281%2F2%29+%2A+%2890+-+A%29+=+%281%2F6%29+%2A+%28180+-+A%29+%2B+1\"
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document.write( "\"%2890+-+A%29%2F2+=+%28180+-+A%29%2F6+%2B+1\"
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document.write( "3(90 - A) = 180 - A + 6 ------ Multiplying by LCD, 6
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document.write( "270 - 3A = 186 - A
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document.write( "- 3A + A = 186 - 270
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document.write( "- 2A = - 84
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document.write( "A, or measure of angle = \"highlight_green%28matrix%281%2C3%2C+%28-+84%29%2F%28-+2%29%2C+or%2C+42%5Eo%29%29\"
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document.write( "It's that easy....nothing COMPLEX!! \n" );
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