document.write( "Question 1057718: x=4x^3-4x \n" ); document.write( "

Algebra.Com's Answer #673021 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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x = 4x^3 - 4x
\n" ); document.write( "Rearrange this to
\n" ); document.write( "4x^3 - 4x - x = 0
\n" ); document.write( "4x^3 - 5x = 0
\n" ); document.write( "factor out x
\n" ); document.write( "x(4x^2 - 5) = 0
\n" ); document.write( "x = 0
\n" ); document.write( "and
\n" ); document.write( "4x^2 = 5
\n" ); document.write( "x^2 = 5/4
\n" ); document.write( "x = +/- $\"sqrt%285%2F4%29\"$
\n" ); document.write( "x = +/- 1.118 \n" ); document.write( "

\n" );