document.write( "Question 13249: Find all points having an x -coordinate of 2 whose distance from the point (-2,-1) is 5? I think it uses distance formula or a midpoint formula. \n" ); document.write( "
Algebra.Com's Answer #6730 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
The points you need to find are (2, y) such that the distance from (2,y) to (-2, -1) is 5. You are right to use the distance formula!!\r
\n" ); document.write( "\n" ); document.write( "\"+sqrt%28+%282-%28-2%29%29%5E2+%2B+%28y-%28-1%29%29%5E2%29+=+5\"\r
\n" ); document.write( "\n" ); document.write( "Square both sides of the equation:
\n" ); document.write( "\"+%284%29%5E2+%2B+%28y%2B1%29%5E2+=+25+\"
\n" ); document.write( "\"+16+%2B+%28y%2B1%29%5E2+=+25+\"
\n" ); document.write( "\"+%28y%2B1%29%5E2+=+9\"\r
\n" ); document.write( "\n" ); document.write( "\"+y%2B1+=+3\" or \"y%2B1=-3\"
\n" ); document.write( "y=3-1; or y = -3 -1
\n" ); document.write( "y = 2 or y = -4\r
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\n" ); document.write( "\n" ); document.write( "The points are (2,2) and (2, -4).\r
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\n" ); document.write( "\n" ); document.write( "Check: Distance from (2,2) to (-2, -1) = \"sqrt+%284%5E2+%2B+3%5E2%29+=+5\"
\n" ); document.write( "Distance from (2,-4) to (-2, -1) = \"sqrt+%284%5E2+%2B+3%5E2%29+=+5\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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