document.write( "Question 1057942: A recent poll of 380 randomly selected Americans showed that 24% (\r
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document.write( " = 0.24) are happy with their cell phone carriers.
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document.write( "The country’s largest cell phone carrier would like to know, within a 90% confidence level, the margin of error for this poll. (90% confidence level z*-score of 1.645)
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document.write( "Remember, the margin of error, E, can be determined using the formula E = z*\r
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document.write( "To the nearest tenth of a percent, the margin of error for the poll is %. \n" );
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Algebra.Com's Answer #672942 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A recent poll of 380 randomly selected Americans showed that 24% ( \n" ); document.write( "= 0.24) are happy with their cell phone carriers. \n" ); document.write( "----------------------------------- \n" ); document.write( "The country’s largest cell phone carrier would like to know, within a 90% confidence level, the margin of error for this poll. (90% confidence level z*-score of 1.645) \n" ); document.write( "Remember, the margin of error, E, can be determined \n" ); document.write( "using the formula E = z*sqrt(pq/n) \n" ); document.write( "----- \n" ); document.write( "E = 1.645*sqrt[0.24*0.76/380] = 0.0360..\r \n" ); document.write( "\n" ); document.write( "To the nearest tenth of a percent, \n" ); document.write( "the margin of error for the poll is 3.6% \n" ); document.write( "--------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------- \n" ); document.write( " |