document.write( "Question 1057917: Please help me.
\n" ); document.write( "A truck travels 450 km to a delivery point, unloads, and, now empty, returns to the starting point at a speed 8.00 km/h greater than on the outward trip. What was the speed of the outward trip if the total round-trip driving time was 14.4 h? Keep three significant digits.
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Algebra.Com's Answer #672919 by jorel555(1290)\"\" \"About 
You can put this solution on YOUR website!
Let s be the speed of the truck going toward the delivery point. Then the return trip would be s+8. So:
\n" ); document.write( "450/s + 450/s+8=14.4
\n" ); document.write( "450(s+8)+450s=14.4sē+115.2s
\n" ); document.write( "14.4sē-784.8s-3600=0
\n" ); document.write( "144sē-7848s-36000=0
\n" ); document.write( "Using the quadratic formula, we get two roots as a solution:-4.25495992697 and 58.754959927. Discarding the negative result, we get the outward trip speed as 58.755 kph. ☺☺☺☺
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