document.write( "Question 92430: please help me thank you\r
\n" ); document.write( "\n" ); document.write( "one number is 12 more than another.The sum of the smaller number and twice the larger number is 39.Find the larger.
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Algebra.Com's Answer #67287 by anraymer(35)\"\" \"About 
You can put this solution on YOUR website!
One number is 12 more than another:
\n" ); document.write( "\"x+=+12+%2B+y\"
\n" ); document.write( "Sum of the smaller number (y) and twice the larger number (x) is 39:
\n" ); document.write( "\"y+%2B+2x+=+39\"\r
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\n" ); document.write( "\n" ); document.write( "Find the larger. Start by taking the second equation and solving for x by subtracting y from both sides:
\n" ); document.write( "\"2x+=+39+-+y\"
\n" ); document.write( "Then divide both sides by 2 to get the x by itself:
\n" ); document.write( "\"x+=+%2839+-+y%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Now you can substitute that answer into the first equation:
\n" ); document.write( "\"%2839+-+y%29%2F2+=+12+%2B+y\"
\n" ); document.write( "Multiply both sides by 2 to get rid of the denominator:
\n" ); document.write( "\"39+-+y+=+%2812+%2B+y%292\"
\n" ); document.write( "\"39+-+y+=+24+%2B+2y\"
\n" ); document.write( "Add y to both sides:
\n" ); document.write( "\"39+=+24+%2B+2y+%2B+y\"
\n" ); document.write( "\"39+=+24+%2B+3y\"
\n" ); document.write( "Subtract 24 from both sides:
\n" ); document.write( "\"39+-+24+=+3y\"
\n" ); document.write( "\"15+=+3y\"
\n" ); document.write( "\"5+=+y\"\r
\n" ); document.write( "\n" ); document.write( "Now you can plug in the value for y to get the answer:
\n" ); document.write( "\"x+=+12+%2B+y\"
\n" ); document.write( "\"x+=+12+%2B+5\"
\n" ); document.write( "\"x+=+17\"
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