document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1057851>Question 1057851</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 17. One number is three less than four times the other. What are the numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #672861 by </B><A HREF=/tutors/aboutme.mpl?userid=solve_for_x><B>solve_for_x(190)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solve_for_x><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=672861\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x represent one number, and let y represent the other number.\r<BR>\n" );
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document.write( "Since the sum of the two numbers is 17, you can write the following <BR>\n" );
document.write( "equation:\r<BR>\n" );
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document.write( "x + y = 17\r<BR>\n" );
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document.write( "Then, since \"one number is three less than 4 times the other\", you can<BR>\n" );
document.write( "write:\r<BR>\n" );
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document.write( "x = 4y - 3\r<BR>\n" );
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document.write( "Substituting \"4y - 3\" in place of x in the first equation gives:\r<BR>\n" );
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document.write( "4y - 3 + y = 17\r<BR>\n" );
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document.write( "5y - 3 = 17\r<BR>\n" );
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document.write( "5y = 20\r<BR>\n" );
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document.write( "y = 4\r<BR>\n" );
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document.write( "Then x = 17 - y = 17 - 4 = 13\r<BR>\n" );
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document.write( "Solution: The two numbers are 4 and 13. </SPAN>\n" );
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