document.write( "Question 1057838: A pellet gun fires ten 3.00 g pellets per second with a speed of 530 m/s. The pellets are stopped by a rigid wall. What is the average force (in newtons) exerted by the pellets on the wall? \n" ); document.write( "
Algebra.Com's Answer #672857 by ikleyn(52847)\"\" \"About 
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document.write( "It is about and around this equation \r\n" );
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document.write( "Ft = mV     (or  Ft = n*(mV) \"= 10*(mV)\" )\r\n" );
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document.write( "(\"the impulse of the force is equal to the change of the momentum\").\r\n" );
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document.write( "The momentum change is n*(m*V) = 10*(3*530) g*m/s.\r\n" );
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document.write( "The time is 1 second.\r\n" );
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document.write( "Therefore, the averaged force is \"F%5Baveraged%5D\" = \"%28n%2Am%2AV%29%2Ft\" = \"10%2A3%2A530%29%2F1\" = calculate.\r\n" );
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document.write( "But still keep in mind that the \"real\" force of one/each separate strike can be significantly different from the averaged force.\r\n" );
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document.write( "Because the interaction time can be significantly shorter than \"1%2F10\" of a second.\r\n" );
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