document.write( "Question 1057708: Twice the sum of x+8 is less than or equal to 16 \n" ); document.write( "
Algebra.Com's Answer #672846 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"2%2A%28x%2B8%29+%3C=+16\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Ax%2B2%2A8+%3C=+16\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B16+%3C=+16\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B16-16+%3C=+16-16\" Subtract 16 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"2x+%3C=+0\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2F2+%3C=+0%2F2\" Divide both sides by 2 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x+%3C=+0\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So the final answer is \"x+%3C=+0\" which is read as \"x is less than or equal to 0\"
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