document.write( "Question 1057709: -kx + y = 3
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document.write( "4x - y = 2
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document.write( "What value of k will make the system consistent? Thank you \n" );
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Algebra.Com's Answer #672815 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! -kx + y = 3 \n" ); document.write( "4x - y = 2 \n" ); document.write( "What value of k will make the system consistent? \n" ); document.write( ": \n" ); document.write( "Use elimination \n" ); document.write( "-kx + y = 3 \n" ); document.write( "+4x - y = 2 \n" ); document.write( "---------------Addition eliminate y \n" ); document.write( "4x - kx = 5 \n" ); document.write( "Factor out x \n" ); document.write( "x(4-k) = 5 \n" ); document.write( "divide both sides by (4-k) \n" ); document.write( "x = \n" ); document.write( "make k = -1 \n" ); document.write( "x = \n" ); document.write( "x = \n" ); document.write( "x = \n" ); document.write( "x = 1 \n" ); document.write( "find y \n" ); document.write( "4(1) - y = 2 \n" ); document.write( "-y = 2 - 4 \n" ); document.write( "-y = -2 \n" ); document.write( "therefore \n" ); document.write( "y = 2 \n" ); document.write( ": \n" ); document.write( "Solution pair: 1,2, consistent when k=-1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |