document.write( "Question 1057709: -kx + y = 3
\n" ); document.write( "4x - y = 2
\n" ); document.write( "What value of k will make the system consistent? Thank you
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Algebra.Com's Answer #672815 by ankor@dixie-net.com(22740)\"\" \"About 
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-kx + y = 3
\n" ); document.write( "4x - y = 2
\n" ); document.write( "What value of k will make the system consistent?
\n" ); document.write( ":
\n" ); document.write( "Use elimination
\n" ); document.write( "-kx + y = 3
\n" ); document.write( "+4x - y = 2
\n" ); document.write( "---------------Addition eliminate y
\n" ); document.write( "4x - kx = 5
\n" ); document.write( "Factor out x
\n" ); document.write( "x(4-k) = 5
\n" ); document.write( "divide both sides by (4-k)
\n" ); document.write( "x = \"5%2F%28%284-k%29%29\"
\n" ); document.write( "make k = -1
\n" ); document.write( "x = \"5%2F%28%284-%28-1%29%29%29\"
\n" ); document.write( "x = \"5%2F%28%284%2B1%29%29\"
\n" ); document.write( "x = \"5%2F5\"
\n" ); document.write( "x = 1
\n" ); document.write( "find y
\n" ); document.write( "4(1) - y = 2
\n" ); document.write( "-y = 2 - 4
\n" ); document.write( "-y = -2
\n" ); document.write( "therefore
\n" ); document.write( "y = 2
\n" ); document.write( ":
\n" ); document.write( "Solution pair: 1,2, consistent when k=-1\r
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