document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1057812>Question 1057812</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dan has 21 coins, all nickels, dimes, and quarters worth $3.35. If he has 4 more quarters than dimes, how many of each coin does he have. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #672812 by </B><A HREF=/tutors/aboutme.mpl?userid=solve_for_x><B>solve_for_x(190)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solve_for_x><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=672812\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let D represent the number of dimes, and let N represent the number of nickels.\r<BR>\n" );
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document.write( "Since Dan has 4 more quarters than dimes, the number of quarters can be represented as D + 4.\r<BR>\n" );
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document.write( "The total number of coins is:\r<BR>\n" );
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document.write( "(Number of quarters) + (Number of dimes) + (Number of nickels) = 21\r<BR>\n" );
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document.write( "(D + 4) + D + N = 21\r<BR>\n" );
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document.write( "2D + N + 4 = 21\r<BR>\n" );
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document.write( "2D + N = 17\r<BR>\n" );
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document.write( "The total value of the coins can be written as:\r<BR>\n" );
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document.write( "($0.25)(Number of quarters) + ($0.10)(Number of dimes) + ($0.05)(Number of nickels) = $3.35\r<BR>\n" );
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document.write( "(0.25)(D + 4) + (0.10)(D) + (0.05)(N) = 3.35\r<BR>\n" );
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document.write( "0.25D + 1 + 0.10D + 0.05N = 3.35\r<BR>\n" );
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document.write( "0.35D + 0.05N = 2.35\r<BR>\n" );
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document.write( "This gives a system of two equations:\r<BR>\n" );
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document.write( "2D + N = 17<BR>\n" );
document.write( "0.35D + 0.05N = 2.35\r<BR>\n" );
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document.write( "This system can be solved simultaneously to get values for D and N. With the value of D, you can get the number of quarters by adding 4 to D. </SPAN>\n" );
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