document.write( "Question 1057765: Airplane A travels 1400 km at a certain speed. Plane B travels 1000 km at a speed 50 km/ h faster than plane A in 3 hrs less time. Find the speed of each plane. \n" ); document.write( "
Algebra.Com's Answer #672776 by jorel555(1290)\"\" \"About 
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Let s be the speed of the slower plane. Then the faster plane flies at s+50. So:
\n" ); document.write( "1400/s - 3=1000/(s+50)
\n" ); document.write( "1400(s+50)- 3sē-150s=1000s
\n" ); document.write( "3sē-250s-70000=0
\n" ); document.write( "(3s+ 350)(s-200)=0
\n" ); document.write( "s=200 or -350/3
\n" ); document.write( "The slower plane flies at 200 kph; the faster one flies 250 kph. ☺☺☺☺ \n" ); document.write( "
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