document.write( "Question 1057650: ln(x-3)-ln(x+10)=ln(x-4)-ln(x+4) \n" ); document.write( "
Algebra.Com's Answer #672716 by solve_for_x(190)\"\" \"About 
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Using the following law of logarithms:\r
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\n" ); document.write( "\n" ); document.write( "ln(a) - ln(b) = ln(a/b)\r
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\n" ); document.write( "\n" ); document.write( "the equation can be rewritten as:\r
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\n" ); document.write( "\n" ); document.write( "\"ln%28%28x-3%29%2F%28x%2B10%29%29+=+ln%28%28x+-+4%29%2F%28x+%2B+4%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "If ln(a) = ln(b), then a = b. Applying this to the above equation gives:\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28x-3%29%2F%28x%2B10%29%29+=+%28%28x+-+4%29%2F%28x+%2B+4%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Multiplying both sides by (x + 10)(x + 4) then gives:\r
\n" ); document.write( "\n" ); document.write( "(x - 3)(x + 4) = (x - 4)(x + 10)\r
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\n" ); document.write( "\n" ); document.write( "Using the FOIL method to expand the terms on both sides gives:\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 3x + 4x - 12 = x^2 - 4x + 10x - 40\r
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\n" ); document.write( "\n" ); document.write( "x^2 + x - 12 = x^2 + 6x - 40\r
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\n" ); document.write( "\n" ); document.write( "Subtracting x^2 from both sides leaves:\r
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\n" ); document.write( "\n" ); document.write( "x - 12 = 6x - 40\r
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\n" ); document.write( "\n" ); document.write( "6x - 40 = x - 12\r
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\n" ); document.write( "\n" ); document.write( "Adding 40 to both sides gives:\r
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\n" ); document.write( "\n" ); document.write( "6x = x - 12 + 40\r
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\n" ); document.write( "\n" ); document.write( "6x = x + 28\r
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\n" ); document.write( "\n" ); document.write( "Subtracting x from both sides then gives:\r
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\n" ); document.write( "\n" ); document.write( "6x - x = 28\r
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\n" ); document.write( "\n" ); document.write( "5x = 28\r
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\n" ); document.write( "\n" ); document.write( "Dividing both sides by 5 then gives:\r
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\n" ); document.write( "\n" ); document.write( "x = 28/5
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