document.write( "Question 1057668: The sum of the second and third terms of a geometric progression is six times the fourth term. Find the two possible values of the common ratio. \n" ); document.write( "
Algebra.Com's Answer #672684 by ikleyn(52799)\"\" \"About 
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\n" ); document.write( "The sum of the second and third terms of a geometric progression is six times the fourth term.
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document.write( "The condition says\r\n" );
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document.write( "\"ar+%2B+ar%5E2\" = \"6ar%5E3\"\r\n" );
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document.write( "where \"a\" is the first term and \"r\" is the common ratio.\r\n" );
document.write( "It leads to the equation\r\n" );
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document.write( "\"6r%5E2+-+r+-+1\" = 0,  or, in the factorized form\r\n" );
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document.write( "(2r-1)*(3r+1) = 0.\r\n" );
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document.write( "The roots are \"1%2F2\" and \"-1%2F3\".\r\n" );
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document.write( "It is your answer.\r\n" );
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