document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1057615>Question 1057615</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a car travels 1 mile at 30mph and then travels another mile at 60mph what is the average speed?....is the answer 40mph or 45mph?. Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #672640 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=672640\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using rate * time = distance, we have two formulas<BR>\n" );
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document.write( "1) t1 = 1/30<BR>\n" );
document.write( "2) t2 = 1/60<BR>\n" );
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document.write( "total time t = 1 * ( 1/30 + 1/60 )<BR>\n" );
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document.write( "average speed = (2 * 1) / ( 1 * ( 1/30 + 1/60 ) ) = 2 / ( 1/30 + 1/60 ) = 40 mph<BR>\n" );
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