document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1057603>Question 1057603</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An assembly line worker at Rob’s Bicycle factory adds a seat to\r<BR>\n" );
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document.write( "a bicycle at a rate of 2 seats in 11 minutes. Write a proportion relating the \r<BR>\n" );
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document.write( "number of seats s to the number of minutes m. At this rate, how long will \r<BR>\n" );
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document.write( "it take to add 16 seats? 19 seats?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #672633 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=672633\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 seats/11 minutes=16 seats/x minutes.<BR>\n" );
document.write( "Can cross-multiply, so that 2x=16*11=176 and x=88 minutes.<BR>\n" );
document.write( "Also note that 16 is 8 x as many seats, so the time is 8*11 minutes.<BR>\n" );
document.write( "For 19 seats, this is 2/11=19/x<BR>\n" );
document.write( "Cross-multiply and get 2x=209 and x=104.5 minutes<BR>\n" );
document.write( "Alternatively, one can say 2 seats in 11 minutes and 1 seat in 5 1/2 minutes.<BR>\n" );
document.write( "Multiply 16 by 5(1/2) and get 88<BR>\n" );
document.write( "multiply 19 by 5 (1/2) and get 104.5 </SPAN>\n" );
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