document.write( "Question 92159: Find the solution sets for the following:\r
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document.write( "2/ x+1 + 6 = 3/x-1 \n" );
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Algebra.Com's Answer #67258 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Find the solution sets for the following: \n" ); document.write( "Assume you mean: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply each term in the equation by (x+1)(x-1), results in: \n" ); document.write( "2(x-1) + 6(x+1)(x-1) = 3(x+1) \n" ); document.write( ": \n" ); document.write( "2x - 2 + 6(x^2 - 1) = 3x + 3; FOILed (x+1)*(x-1) \n" ); document.write( "2x - 2 + 6x^2 - 6 = 3x + 3 \n" ); document.write( ": \n" ); document.write( "Arrange as a quadratic equation on the left: \n" ); document.write( "6x^2 + 2x - 3x - 2 - 6 - 3 = 0 \n" ); document.write( ": \n" ); document.write( "6x^2 - x - 11 = 0 \n" ); document.write( ": \n" ); document.write( "Use the quadratic formula to find x: a=6; b=-1; c=-11 \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Two solutions: \n" ); document.write( " \n" ); document.write( "x = \n" ); document.write( "x = +1.44 \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "x = \n" ); document.write( "x = -1.273 \n" ); document.write( ": \n" ); document.write( "You should check these solutions in the original equation. \n" ); document.write( " |