document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1057484>Question 1057484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An oval athletic field is the union of a square and semicircles at opposite ends, as shown in the figure below (http://www.webassign.net/jmodd7/8-1-034.gif). If the total area of the field is 1,300 square yards, find the dimensions of the square.\r<BR>\n" );
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document.write( "So I know that we have to separate the shapes, and assemble the circles. I let S equal the sides of the square, and s also represents the radius, which is half the diameter.\r<BR>\n" );
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document.write( "We are given the area, which is 1300. What I don't understand is how to incorporate this into the problem to get the answer. I was provided with a formula, but am not sure how to solve for x.\r<BR>\n" );
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document.write( "A=s^2+3.14*(s/2)^2+s^2+(1+3.14/4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #672525 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=672525\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An oval athletic field is the union of a square and semicircles at opposite ends, as shown in the figure below (http://www.webassign.net/jmodd7/8-1-034.gif).<BR>\n" );
document.write( " If the total area of the field is 1,300 square yards, find the dimensions of the square.<BR>\n" );
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document.write( "Actually s also represents the diameter of the semi-circle; r = .5s<BR>\n" );
document.write( "Two semi-circles = 1 circle<BR>\n" );
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document.write( "Square area + circle area = 1300<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%5E2+%2B+pi%2A%28.5s%29%5E2 ALIGN=MIDDLE  ALT=\"s%5E2+%2B+pi%2A%28.5s%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1300<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%5E2+%2B+pi%2A.25s%5E2 ALIGN=MIDDLE  ALT=\"s%5E2+%2B+pi%2A.25s%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1300<BR>\n" );
document.write( "Factor out s^2<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%5E2%281%2B.25%2Api%29=+1300 ALIGN=MIDDLE  ALT=\"s%5E2%281%2B.25%2Api%29=+1300\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "divide both sides by (1+.25pi0<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%5E2+=+1300%2F%281%2B.25%2Api%29 ALIGN=MIDDLE  ALT=\"s%5E2+=+1300%2F%281%2B.25%2Api%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "use your calc<BR>\n" );
document.write( "s^2 = 728.129<BR>\n" );
document.write( "s = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28728.129%29 ALIGN=MIDDLE  ALT=\"sqrt%28728.129%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "s = 26.98 ~ 27 yards, one side of the square<BR>\n" );
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document.write( "Check this on your calc; radius=13.5<BR>\n" );
document.write( "27^2 + pi*13.5^2 = 1301.55, Because we rounded it off<BR>\n" );
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