document.write( "Question 13356: Invest $30,000 and receive $2,300 in interest. Part was invested at 10% and remainder at 5%. How much was invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #6725 by rapaljer(4671) $\"\"$ $\"About$

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Let x = amount invested at 10%
\n" ); document.write( "30000 - x = amount invested at 5%\r
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\n" ); document.write( "\n" ); document.write( ".10 x + .05(30000 - x) = 2300
\n" ); document.write( ".10x + 1500 - .05x = 2300
\n" ); document.write( ".05x + 1500 = 2300
\n" ); document.write( ".05x = 800
\n" ); document.write( " $\"x+=+800%2F.05+=+80000%2F5+=+16000\"$ at 10%
\n" ); document.write( " $\"30000+-+16000+=+14000+\"$ at 5%\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( ".10($16000) + .05($14000)
\n" ); document.write( "$1600 + $700 = $2300\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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