document.write( "Question 1057369: A circular swimming pool has diameter 50 feet and is centered in a fenced-in square region measuring 80 feet by 80 feet. A concrete sidewalk 5 feet wide encircles the pool, and the rest of the region is grass, as shown in the figure below. (I added a link to the picture used in the problem. https://www.dropbox.com/s/jxc7syj05xb0lrh/8-1-023.gif?dl=0 )\r
\n" ); document.write( "\n" ); document.write( "Find the surface area of the water
\n" ); document.write( " Find the area of the concrete sidewalk
\n" ); document.write( "Find the area of the grass\r
\n" ); document.write( "\n" ); document.write( "Some of these I believe I can solve (sidewalk and grass area), but the surface area is something I have not done in about 15 years, and I am very rusty with it.
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Algebra.Com's Answer #672428 by solve_for_x(190)\"\" \"About 
You can put this solution on YOUR website!
It is easiest to start with the water surface and work your way outward.\r
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\n" ); document.write( "\n" ); document.write( "The surface area of the water is just the area of the circle: \"pi%2Ad%5E2%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Since the diameter is d = 50 ft, the surface area is \"pi%2A50%5E2%2F4\" = 1963.5 sq. ft\r
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\n" ); document.write( "\n" ); document.write( "The 5 ft sidewalk around the perimeter of the pool makes a larger circle, with a diameter of 60 ft.\r
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\n" ); document.write( "\n" ); document.write( "Find the area of this larger circle, and subtract the area of the water surface that was
\n" ); document.write( "calculated above to get the area of the sidewalk:\r
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\n" ); document.write( "\n" ); document.write( "Area of sidewalk = \"pi%2A60%5E2%2F4+-+pi%2A50%5E2%2F4\" = 2827.43 - 1963.50 = 863.93 sq. ft.\r
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\n" ); document.write( "\n" ); document.write( "Finally, the area of the grass is the difference between the area of the fenced region, minus the area of the larger circle (2827.43 sq. ft):\r
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\n" ); document.write( "\n" ); document.write( "Area of grass = (80 * 80) - 2827.43 = 3,572.57 sq. ft.
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