document.write( "Question 1057369: A circular swimming pool has diameter 50 feet and is centered in a fenced-in square region measuring 80 feet by 80 feet. A concrete sidewalk 5 feet wide encircles the pool, and the rest of the region is grass, as shown in the figure below. (I added a link to the picture used in the problem. https://www.dropbox.com/s/jxc7syj05xb0lrh/8-1-023.gif?dl=0 )\r
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document.write( "Find the surface area of the water
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document.write( " Find the area of the concrete sidewalk
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document.write( "Find the area of the grass\r
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document.write( "Some of these I believe I can solve (sidewalk and grass area), but the surface area is something I have not done in about 15 years, and I am very rusty with it. \n" );
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Algebra.Com's Answer #672428 by solve_for_x(190)![]() ![]() ![]() You can put this solution on YOUR website! It is easiest to start with the water surface and work your way outward.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The surface area of the water is just the area of the circle: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the diameter is d = 50 ft, the surface area is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The 5 ft sidewalk around the perimeter of the pool makes a larger circle, with a diameter of 60 ft.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Find the area of this larger circle, and subtract the area of the water surface that was \n" ); document.write( "calculated above to get the area of the sidewalk:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Area of sidewalk = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Finally, the area of the grass is the difference between the area of the fenced region, minus the area of the larger circle (2827.43 sq. ft):\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Area of grass = (80 * 80) - 2827.43 = 3,572.57 sq. ft. \n" ); document.write( " |