document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1057369>Question 1057369</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circular swimming pool has diameter 50 feet and is centered in a fenced-in square region measuring 80 feet by 80 feet. A concrete sidewalk 5 feet wide encircles the pool, and the rest of the region is grass, as shown in the figure below. (I added a link to the picture used in the problem. https://www.dropbox.com/s/jxc7syj05xb0lrh/8-1-023.gif?dl=0 )\r<BR>\n" );
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document.write( "Find the surface area of the water<BR>\n" );
document.write( " Find the area of the concrete sidewalk<BR>\n" );
document.write( "Find the area of the grass\r<BR>\n" );
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document.write( "Some of these I believe I can solve (sidewalk and grass area), but the surface area is something I have not done in about 15 years, and I am very rusty with it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #672427 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=672427\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A circular swimming pool has diameter 50 feet and is centered in a fenced-in square region measuring 80 feet by 80 feet. A concrete sidewalk 5 feet wide encircles the pool, and the rest of the region is grass, as shown in the figure below. (I added a link to the picture used in the problem. https://www.dropbox.com/s/jxc7syj05xb0lrh/8-1-023.gif?dl=0 )\r<BR>\n" );
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document.write( "Find the surface area of the water<BR>\n" );
document.write( "-- Area = pi*r^2 = pi*25^2 = 625pi sq feet.<BR>\n" );
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document.write( "Find the area of the concrete sidewalk<BR>\n" );
document.write( "r to the outside of the concrete = 25+5 = 30 feet<BR>\n" );
document.write( "Area = pi*30^2 - area of the water<BR>\n" );
document.write( "= 900pi - 625pi sq feet = 225pi sq feet<BR>\n" );
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document.write( "Find the area of the grass<BR>\n" );
document.write( "= 80*80 - the other 2 areas<BR>\n" );
document.write( "= 6400 - 900pi sq ft.<BR>\n" );
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