document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13358>Question 13358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me to solve: 10-3x=2x-8x+40 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6724 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6724\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Combine like terms on the right side:\r<BR>\n" );
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document.write( "10-3x=2x-8x+40<BR>\n" );
document.write( "10-3x=-6x+40\r<BR>\n" );
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document.write( "Add +6x to both sides to get all x terms to the left side:<BR>\n" );
document.write( "10 - 3x + 6x = -6x + 6x + 40<BR>\n" );
document.write( "10 + 3x = 40\r<BR>\n" );
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document.write( "Subtract 10 from each side:<BR>\n" );
document.write( "10 - 10 + 3x  = 40 - 10<BR>\n" );
document.write( "3x = 30\r<BR>\n" );
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document.write( "x= 10\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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