document.write( "Question 1057343: Supposed that in a certain association,there are 12 elected members of the board of directors.In how many ways can a president,a vice president,a secretary,and a treasurer be selectes from the bored? \n" ); document.write( "

Algebra.Com's Answer #672398 by solve_for_x(190) $\"\"$ $\"About$

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Since the positions are titled (i.e. president, vice president, etc), the order matters. Thus
\n" ); document.write( "this is a problem involving permutations.\r
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\n" ); document.write( "\n" ); document.write( "The number of permutations of 4 items, selected from a pool of 12 items is:\r
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\n" ); document.write( "\n" ); document.write( " $\"P%2812%2C+4%29+=+12%21%2F%2812-4%29%21+=+12%21%2F8%21+=+11880\"$ \r
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\n" ); document.write( "\n" ); document.write( "Another way to look at this is that there are 12 possible selections for president,
\n" ); document.write( "and then 11 possible selections for vice president, and then 10 possible selections
\n" ); document.write( "for secretary, and finally 9 possible selections for treasurer. Combining all four
\n" ); document.write( "selections gives:\r
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\n" ); document.write( "\n" ); document.write( "12 * 11 * 10 * 9 = 11,880 possible arrangements. \n" ); document.write( "

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