document.write( "Question 1057158: the local amateur football club spent $675 on tickets to a professional football game. if the club bought three fewer fifteen dollar tckets than four-fifths the number of twelve dollar tickets, how many tickets of each type did the club buy? \n" ); document.write( "
Algebra.Com's Answer #672387 by solve_for_x(190)![]() ![]() ![]() You can put this solution on YOUR website! Let x represent the number of $12 tickets purchased.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then, the number of $15 tickets is \"three fewer ... than four-fifths the number\" of $12 tickets.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The number of $15 tickets can then be represented as:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(4/5)x - 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The amount collected from the sale of $12 tickets is 12 * x = 12x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The amount collected from the sale of $15 tickets is 15 * [(4/5)x - 3] = 12x - 45.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Together, these amounts must add up to the total ticket sales of $675, which \n" ); document.write( "gives the following equation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "12x + (12x - 45) = 675\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Collecting like terms on the left side gives:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "24x - 45 = 675\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Adding 45 to both sides then gives:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "24x = 720\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Dividing both sides by 24 then leaves:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 30\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is the number of $12 tickets. You can then substitute x = 30 into \"(4/5)x - 3\" \n" ); document.write( "to get the number of $15 tickets. \n" ); document.write( " |