document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1057240>Question 1057240</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a triangle is 79.75 inches. The second side is half as big as the first. the third side is 7.25 inches greater than the first. What is the length of the longest side of the triangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #672386 by </B><A HREF=/tutors/aboutme.mpl?userid=solve_for_x><B>solve_for_x(190)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solve_for_x><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=672386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x represent the length of the first side.\r<BR>\n" );
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document.write( "The second side is half as long as the first, or x/2.\r<BR>\n" );
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document.write( "The third side is 7.25 inches longer than the first, or x + 7.25\r<BR>\n" );
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document.write( "The sum of all three sides must be equal to the perimeter, or 79.75 inches. This gives:\r<BR>\n" );
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document.write( "x + (x/2) + (x + 7.25) = 79.75\r<BR>\n" );
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document.write( "x + 0.5x + x + 7.25 = 79.75\r<BR>\n" );
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document.write( "2.5x + 7.25 = 79.75\r<BR>\n" );
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document.write( "Subtracting 7.25 from both sides leaves:\r<BR>\n" );
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document.write( "2.5x = 72.5\r<BR>\n" );
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document.write( "Dividing by 2.5 then gives:\r<BR>\n" );
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document.write( "x = 29\r<BR>\n" );
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document.write( "From here, you can substitute x = 29 into the expressions for the second and third side to find their lengths. </SPAN>\n" );
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