document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1057253>Question 1057253</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If two angles are complementary, the sum of their angle measures equals 90 degrees. The measure of the two complementary angles are 7x + 17 and 3x - 22. What are the measures of the two angles? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #672342 by </B><A HREF=/tutors/aboutme.mpl?userid=solve_for_x><B>solve_for_x(190)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solve_for_x><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=672342\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the sum of the angles must be 90 degrees, you can write the following equation:\r<BR>\n" );
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document.write( "(7x + 17) + (3x - 22) = 90\r<BR>\n" );
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document.write( "Collecting and combining like terms on the left gives:\r<BR>\n" );
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document.write( "10x - 5 = 90\r<BR>\n" );
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document.write( "Adding 5 to both sides then gives:\r<BR>\n" );
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document.write( "10x = 95\r<BR>\n" );
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document.write( "And dividing both sides by 10 leaves:\r<BR>\n" );
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document.write( "x = 9.5\r<BR>\n" );
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document.write( "Now, substitute x = 9.5 into the expression for each angle:\r<BR>\n" );
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document.write( "First angle: 7(9.5) + 17 = 83.5 degrees\r<BR>\n" );
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document.write( "Second angle: 3(9.5) - 22 = 6.5 degrees\r<BR>\n" );
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document.write( "As a check, add the angles together and make sure that the sum is 90:\r<BR>\n" );
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document.write( "83.5 + 6.5 = 90\r<BR>\n" );
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document.write( "90 = 90\r<BR>\n" );
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document.write( "so the solution checks. </SPAN>\n" );
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