document.write( "Question 1057202: The annual interest $11,000.00 investment exceeds the interest earned on a $9000.00 investment by $184.00. The $11,000.00 investment is at a 0.4% higher rate than tha $9000.00 investment. What is the interest rate of each investment? \n" ); document.write( "
Algebra.Com's Answer #672331 by jorel555(1290)![]() ![]() ![]() You can put this solution on YOUR website! Let n be the interest rate on the smaller investment. Then the interest rate on the larger investment is n+.004. So: \n" ); document.write( "11000(n+.004)-184=9000(n) \n" ); document.write( "11000n-140=9000n \n" ); document.write( "2000n=140 \n" ); document.write( "n=.07 \n" ); document.write( "The interest rate on the $11000 is 7.4%, the rate on the $9000 is 7%. ☺☺☺☺ \n" ); document.write( " |