document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1057233>Question 1057233</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Prove identity:\r<BR>\n" );
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document.write( "2sin(-x)-cotx*sinx*cosx=(sinx-1)^2-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #672320 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=672320\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2sin(-x)-cotx*sinx*cosx=(sinx-1)^2-2<BR>\n" );
document.write( "-2sin (x)-[(cos x/sin x)*sin x* cos x)], because sin is an odd function.<BR>\n" );
document.write( "-2 sin x-cos^2 x=<BR>\n" );
document.write( "-2sin x-1+sin^2 x, since cos ^2 x=1-sin^2 x<BR>\n" );
document.write( "=sin^2x-2sin x -1<BR>\n" );
document.write( "=(sin x-1)^2-2, since the first term is sin^2x-2sin x+1, and we need to get to -1.<BR>\n" );
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