document.write( "Question 92382: x2+y2=25
\n" ); document.write( "xy=12
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Algebra.Com's Answer #67230 by stanbon(75887)\"\" \"About 
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x2+y2=25
\n" ); document.write( "xy=12
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\n" ); document.write( "Solve the 2nd equation for y and substitute into the 1st equation.
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\n" ); document.write( "y = 12/x\r
\n" ); document.write( "\n" ); document.write( "x^2+(12/x)^2 = 25\r
\n" ); document.write( "\n" ); document.write( "x^2 + 144/x^2 = 25\r
\n" ); document.write( "\n" ); document.write( "Multiply thru by x^2 to get:\r
\n" ); document.write( "\n" ); document.write( "x^4 + 144 = 25x^2\r
\n" ); document.write( "\n" ); document.write( "x^4 - 25x^2 +144 = 0
\n" ); document.write( "(x^2-9)(x^2-16)=0\r
\n" ); document.write( "\n" ); document.write( "x = 3 or x=4 or x = -3 or x= -4
\n" ); document.write( "correspondingly:
\n" ); document.write( "y= 4 or y=3 or y= -4 or y=-3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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