document.write( "Question 1057242: A collection of coins consisting of dimes and quarters has a value of $2.55. If the number of dimes is 3 more than twice the number of quarters, how many of each type of coin are there? \n" ); document.write( "

Algebra.Com's Answer #672298 by ikleyn(52795) $\"\"$ $\"About$

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\n" ); document.write( "A collection of coins consisting of dimes and quarters has a value of $2.55. If the number of dimes is 3 more
\n" ); document.write( "than twice the number of quarters, how many of each type of coin are there?
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document.write( "From the condition, you have these two equations\r\n" );
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document.write( "10d + 25q = 255,   (1)\r\n" );
document.write( "d = 2q + 3.        (2)\r\n" );
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document.write( "substitute expression (2) to the equation (1), replacing d. You will get\r\n" );
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document.write( "10(2q +3) + 25q = 255,   or\r\n" );
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document.write( "20q + 30 + 25q = 255,  or\r\n" );
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document.write( "45q = 255 - 30,\r\n" );
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document.write( "45q = 225.\r\n" );
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document.write( "q =  = 5\r\n" );
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document.write( "5 quarters and 2*5 + 3 = 13 dimes.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Sorry, it was MY mistake.\r
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