document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1057094>Question 1057094</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It took a plane 2 hours to go from Dallas to NY with the head wind and 1.5 hours to get back with the tail wind. If the speed of the wind was 30 mph, how far apart are two cities?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #672285 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=672285\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let a equal the airspeed of the plane in still air; and d be the distance between the two cities. Then:<BR>\n" );
document.write( "d/a+30=1.5<BR>\n" );
document.write( "d=1.5a+45<BR>\n" );
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document.write( "d/a-30=2<BR>\n" );
document.write( "d=2a-60<BR>\n" );
document.write( "So<BR>\n" );
document.write( "2a-60=1.5a+45<BR>\n" );
document.write( ".5a=105<BR>\n" );
document.write( "a=210<BR>\n" );
document.write( "d/210-30=2<BR>\n" );
document.write( "d=360<BR>\n" );
document.write( "The distance between the two cities is 360 miles. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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