document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1057204>Question 1057204</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ruth is x years old. In 12 years time, Ruth will be three times as old as she was 6 years ago. Find Ruth's age now. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #672270 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=672270\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+12 = 3(x-6)<BR>\n" );
document.write( "x+12 = 3x-18 Subtract 3x and 12 from both sides<BR>\n" );
document.write( "-2x = -30 divide both sides by -2, and remember -/- = +<BR>\n" );
document.write( "x = 15 Ruth is 15<BR>\n" );
document.write( "------------------------------------<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "15+12 = 3(15-6)<BR>\n" );
document.write( "15+12 = 45-18<BR>\n" );
document.write( "27 = 27 Correct.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "John<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );