document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1057115>Question 1057115</A>: <I><SPAN STYLE=\"word-break: break-all;\"> would you please solve the following problem?\r<BR>\n" );
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document.write( "Plastic Box A has a square base of area 36 cm² and a height of 8 cm. It is completely filled with juice. Plastic Box B is empty and has dimensions 5 cm by 3 cm by 12 cm. Juice from Box A is poured into Box B until it is filled to the very top. Find the height of the new juice level in Box A. \r<BR>\n" );
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document.write( "-Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #672194 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=672194\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Volume of A:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=36cm%5E2+%2A+8cm+=+288cm%5E3+ ALIGN=MIDDLE  ALT=\"36cm%5E2+%2A+8cm+=+288cm%5E3+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Volume of B:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+5cm%2A3cm%2A12cm+=+180cm%5E3+ ALIGN=MIDDLE  ALT=\"+5cm%2A3cm%2A12cm+=+180cm%5E3+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "When A is poured into B, that \"subtracts\"  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=180cm%5E3 ALIGN=MIDDLE  ALT=\"180cm%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" > from A.   So <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=288cm%5E3-180cm%5E3+=+108cm%5E3 ALIGN=MIDDLE  ALT=\"288cm%5E3-180cm%5E3+=+108cm%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" > are remaining in A.   If we divide that volume by the area of the base, we'll get the height:\r<BR>\n" );
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document.write( " <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=108cm%5E3+%2F+%2836cm%5E2%29+=+3cm+ ALIGN=MIDDLE  ALT=\"108cm%5E3+%2F+%2836cm%5E2%29+=+3cm+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Ans:  The juice will have a height of 3cm in box A after filling box B.<BR>\n" );
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document.write( "NOTE: this problem can also be easily solved using a proportion.  The <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=108cm%5E3 ALIGN=MIDDLE  ALT=\"108cm%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" > volume remaining is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F8 ALIGN=MIDDLE  ALT=\"3%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" > of the original <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=288cm%5E3 ALIGN=MIDDLE  ALT=\"288cm%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" > volume so the height would be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283%2F8%29%2A+8cm+=+3cm+ ALIGN=MIDDLE  ALT=\"%283%2F8%29%2A+8cm+=+3cm+\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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