document.write( "Question 1057063: Please solve this system using substitution.
\n" ); document.write( " 4x-y=5
\n" ); document.write( " 4x+4y=-4\r
\n" ); document.write( "\n" ); document.write( "Thank you,
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Algebra.Com's Answer #672186 by math_helper(2461)\"\" \"About 
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4x-y = 5 (eq 1)
\n" ); document.write( "4x+4y = -4 (eq 2)\r
\n" ); document.write( "\n" ); document.write( "From (eq 1): y=4x-5
\n" ); document.write( "Substitute this expression for 'y' in eq 2:\r
\n" ); document.write( "\n" ); document.write( "4x+4(4x-5) = -4
\n" ); document.write( "4x+16x-20 = -4
\n" ); document.write( "20x = 16
\n" ); document.write( "x = 16/20 = 4/5, y = 4(4/5) - 5 = -9/5\r
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\n" ); document.write( "Ans: x = 4/5, y = -9/5
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "(eq1) 4x-y = 4(4/5)-(-9/5) = 25/5 = 5 (ok)
\n" ); document.write( "(eq2) 4x+4y = 4(4/5) + 4(-9/5) = 16/5-36/5 = -20/5 = -4 (ok)\r
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