document.write( "Question 1056999: Martina drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 10 hours. When Martina drove home, there was no traffic and the trip only took 7 hours. If her average rate was 18 mph faster on the trip home, how far away does Martina live from the mountains? \n" ); document.write( "
Algebra.Com's Answer #672078 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( " Martina drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 10 hours. When Martina drove home, there was no traffic and the trip only took 7 hours. If her average rate was 18 mph faster on the trip home, how far away does Martina live from the mountains?
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With D being the distance, the SPEED equation you need is: \"D%2F10+=+D%2F7+-+18\"
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document.write( "7D = 10D - 1,260 ----- Multiplying by LCD, 70
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document.write( "7D - 10D = - 1,260
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document.write( "- 3D = - 1,260
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document.write( "D, or distance = \"highlight_green%28matrix%281%2C4%2C+%22-+1%2C260%22%2F%28-+3%29%2C+or%2C+420%2C+miles%29%29\"
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document.write( "See how easy that was? Nothing complex!! \n" );
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