document.write( "Question 1057002: Latoya's boat has a top speed of 20 mph in still water. While traveling on a river at top speed, she went 40 miles upstream in the same amount of time she went 60 miles downstream. Find the rate of the river current. \n" ); document.write( "

Algebra.Com's Answer #672075 by ikleyn(52794) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "Latoya's boat has a top speed of 20 mph in still water. While traveling on a river at top speed, she went 40 miles upstream
\n" ); document.write( "in the same amount of time she went 60 miles downstream. Find the rate of the river current.
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "Let \"v\" be the rate of the river current.\r\n" );
document.write( "\r\n" );
document.write( "Then the speed of the boat upstream is 20-v mph,\r\n" );
document.write( "while its speed downstream is 20+v mph.\r\n" );
document.write( "\r\n" );
document.write( "The condition says \r\n" );
document.write( "\r\n" );
document.write( " = .\r\n" );
document.write( "\r\n" );
document.write( "It is yours governing equation. \r\n" );
document.write( "To solve it, multiply both sides by (20-v)*(20+v). You will get\r\n" );
document.write( "\r\n" );
document.write( "40*(20+v) = 60*(20-v),   or\r\n" );
document.write( "\r\n" );
document.write( "800 + 40v = 1200 - 60v,\r\n" );
document.write( "\r\n" );
document.write( "40v + 60v = 1200 - 800,\r\n" );
document.write( "\r\n" );
document.write( "100v = 400,\r\n" );
document.write( "\r\n" );
document.write( "v = 4.\r\n" );
document.write( "\r\n" );
document.write( "Answer. The rate of the river current is 4 mph.\r\n" );
document.write( "

\n" ); document.write( " \n" ); document.write( "

\n" );