document.write( "Question 1056985: Boris drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 7 hours. When Boris drove home, there was no traffic and the trip only took 4 hours. If his average rate was 27 miles per hour faster on the trip home, how far away does Boris live from the mountains? \n" ); document.write( "
Algebra.Com's Answer #672059 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Boris drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 7 hours. When Boris drove home, there was no traffic and the trip only took 4 hours. If his average rate was 27 miles per hour faster on the trip home, how far away does Boris live from the mountains?
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With D being the distance, the SPEED equation you need is: \"D%2F7+=+D%2F4+-+27\"
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document.write( "4D = 7D - 756 ----- Multiplying by LCD, 28
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document.write( "4D - 7D = - 756
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document.write( "- 3D = - 756
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document.write( "D, or distance = \"highlight_green%28matrix%281%2C4%2C+%28-+756%29%2F%28-+3%29%2C+or%2C+252%2C+miles%29%29\"
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document.write( "See how easy that was? Nothing complex!! \n" );
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